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登录token优化

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This commit is contained in:
gaoxq
2026-02-27 11:11:02 +08:00
parent 3b228a82ba
commit c677027988
2 changed files with 50 additions and 1 deletions
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48
src/main/java/com/mini/mybigscreen/utils/KeyUtil.java Normal file
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package com.mini.mybigscreen.utils;
import java.util.Random;
public class KeyUtil {
public static String ObjKey(int length, int type) {
Random random = new Random();
StringBuffer key = new StringBuffer();
if (type == 1) {
String str = "0123456789";
for (int i = 0; i < length; ++i) {
//从62个的数字或字母中选择
int number = random.nextInt(10);
//将产生的数字通过length次承载到key中
key.append(str.charAt(number));
}
return key.toString();
} else if (type == 2) {
String str = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
for (int i = 0; i < length; ++i) {
//从62个的数字或字母中选择
int number = random.nextInt(36);
//将产生的数字通过length次承载到key中
key.append(str.charAt(number));
}
return key.toString();
} else if (type == 3) {
String str = "abcdefghijklmnopqrstuvwxyz0123456789";
for (int i = 0; i < length; ++i) {
//从62个的数字或字母中选择
int number = random.nextInt(36);
//将产生的数字通过length次承载到key中
key.append(str.charAt(number));
}
return key.toString();
} else {
String str = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
for (int i = 0; i < length; ++i) {
//从62个的数字或字母中选择
int number = random.nextInt(62);
//将产生的数字通过length次承载到key中
key.append(str.charAt(number));
}
return key.toString();
}
}
}